Power Factor Correction: Optimize Reactive Power and Reduce Losses

simulator beginner ~8 min
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Q_c ≈ 131 kVAR — corrects PF from 0.75 to 0.95

To correct a 200 kW load from power factor 0.75 to 0.95, approximately 131 kVAR of capacitor compensation is required. This reduces apparent power from 267 kVA to 211 kVA and line current by 21%.

Formula

Q_c = P × (tan(arccos(PF_old)) − tan(arccos(PF_new)))
S = P / PF = √(P² + Q²)
PF = P / S = cos(φ)

The Power Triangle

Electrical power has three components: real power P (watts, which performs useful work), reactive power Q (vars, which sustains magnetic fields in motors and transformers), and apparent power S (volt-amperes, which the generator and transmission system must deliver). These form a right triangle where S² = P² + Q², and the power factor is the cosine of the angle between P and S. The visualization shows this triangle dynamically as you adjust parameters.

The Cost of Poor Power Factor

A power factor of 0.75 means the grid must deliver 33% more current than necessary to supply the same real power. Since line losses are proportional to I² (current squared), losses increase by 78%. Transformers, cables, and switchgear must all be oversized to handle this excess current. For a 200 kW load at PF 0.75, the apparent power is 267 kVA — requiring infrastructure rated for 267 kVA even though only 200 kW does useful work.

Capacitor Bank Sizing

The required capacitive reactive power Q_c equals the difference between the reactive power at the old and new power factors: Q_c = P × (tan(arccos(PF_old)) − tan(arccos(PF_new))). Standard capacitor bank sizes come in discrete steps, so engineers round up to the nearest available unit. The simulation accounts for this and shows the actual achieved power factor after installing a standard-sized bank.

Practical Considerations

Real installations use automatic power factor correction (APFC) controllers that switch capacitor banks in and out based on measured power factor. This prevents overcorrection during light load periods and avoids resonance with system harmonics. Modern installations increasingly use static VAR compensators (SVCs) or STATCOMs for faster, smoother, and more precise reactive power control — especially important near renewable energy sources with variable output.

FAQ

What is power factor?

Power factor is the ratio of real power (watts, which do useful work) to apparent power (volt-amperes, which the grid must deliver). A power factor of 1.0 means all power does useful work. Most industrial loads have power factors of 0.7-0.9 due to inductive motors and transformers.

Why does low power factor cost money?

Low power factor means the utility must generate and transmit more current to deliver the same real power. This increases I²R losses in transmission lines, requires larger transformers and cables, and reduces system capacity. Utilities charge penalties for power factor below 0.85-0.90.

How do capacitor banks correct power factor?

Capacitors supply leading reactive power that cancels the lagging reactive power drawn by inductive loads (motors, transformers). This reduces the total reactive power the grid must supply, improving power factor and reducing current.

Can you overcorrect power factor?

Yes. If capacitor banks exceed the inductive reactive demand (especially during light load periods), the power factor becomes leading. This can cause voltage rise, resonance with system inductance, and damage to equipment. Switched capacitor banks avoid this.

Sources

Embed

<iframe src="https://homo-deus.com/lab/power-systems/power-factor/embed" width="100%" height="400" frameborder="0"></iframe>
View source on GitHub