Transistor Amplifier: Common-Emitter BJT Design

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Av = -4.0 — 50 mV in → 200 mV out (inverted)

With Rc=4kΩ and Re=1kΩ, the voltage gain is approximately -4. A 50mV input produces a 200mV inverted output. The operating point sits at Vce ≈ 6V with Ic ≈ 1.2mA.

Formula

Av ≈ -Rc / Re (voltage gain with emitter degeneration)
Ic ≈ (Vcc/2) / (Rc + Re) for midpoint biasing
Vce = Vcc - Ic × (Rc + Re)

The Building Block of Analog Electronics

The common-emitter amplifier is the most fundamental transistor circuit — the configuration that launched the electronics revolution. A single bipolar junction transistor (BJT) with a few resistors can amplify a weak signal from a microphone, sensor, or antenna into a signal strong enough to drive a speaker, display, or transmission line. Understanding this circuit is the gateway to all of analog electronics, from audio amplifiers to radio receivers.

Biasing: Setting the Operating Point

Before a transistor can amplify AC signals, it must be biased into its active region with a stable DC operating point (Q-point). The Q-point determines the collector current Ic and the collector-emitter voltage Vce at rest. Ideal biasing places Vce at approximately half the supply voltage, maximizing the symmetric output swing. This simulator calculates the Q-point from your component values and shows where the transistor sits on its output characteristic.

Gain and the Emitter Resistor

The voltage gain of a common-emitter amplifier with emitter degeneration is approximately Av = -Rc/Re. This elegant formula means the gain depends only on external resistor ratios, not on the transistor's β (which varies wildly between units). The negative sign indicates phase inversion — a hallmark of common-emitter topology. Without Re, the gain shoots up but becomes unpredictable and temperature-sensitive.

From Single Transistor to Op-Amp

The common-emitter stage is rarely used alone in modern circuits — it forms the input stage of differential pairs, which in turn are the building blocks of operational amplifiers. But every op-amp, every processor, every piece of silicon ultimately reduces to transistors doing what this simulator shows: converting small input variations into large output swings through the physics of semiconductor junctions.

FAQ

How does a common-emitter amplifier work?

A small AC signal at the base modulates the base current, which is amplified by the transistor's current gain β to produce a larger collector current. This amplified current flowing through the collector resistor creates a voltage swing at the output. The common-emitter configuration provides both voltage and current gain, making it the most widely used amplifier topology.

What is the role of the emitter resistor?

The emitter resistor Re provides negative feedback (emitter degeneration) that stabilizes the operating point and makes the gain less dependent on β. Without Re, the gain is extremely high but unstable — it depends on the transistor's internal re which varies with temperature and manufacturing. With Re, the gain is approximately -Rc/Re, which is set by external resistors you control.

Why is the output inverted?

When the base voltage increases, base and collector current increase. More current through Rc means more voltage drop across Rc, so the collector voltage decreases. Input goes up, output goes down — a 180° phase inversion. This is characteristic of the common-emitter configuration and is expressed by the negative sign in Av = -Rc/Re.

What causes signal clipping in a transistor amplifier?

Clipping occurs when the output signal tries to swing beyond the supply voltage (Vcc) or below the saturation voltage (Vce_sat ≈ 0.2V). Proper biasing places the Q-point (operating point) midway between these limits, maximizing the undistorted output swing. This simulator shows how the Q-point shifts as you adjust component values.

Sources

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